Postagens

Mostrando postagens de abril, 2026
Imagem
Prof. John was playing an RPG game with his students. He then shows this dice to them and says that it is a dodecahedron and we can represent its vertices and edges as a graph: Four students come up with different observations about the dice: Student 1 says: The planar representation of the dice graph is Student 2 says: The planar representation of the dice graph is Student 3 says: The graph represented by the vertices and edges of the dice is three-dimensional, therefore, not planar. Student 4 says: The standard Euler formula only applies to planar graphs, needing to be adjusted into \(V-E+F=1\) to account for the topological change in regular polyhedra like this dice. Which student is right? A) Student 1. B) Student 2. C) Student 3. D) Student 4. E) None of the above. Original idea by: Rafael Brusiquesi Martins
Imagem
We have this conformation of connected water tanks: We can model the first tank as: \[ \begin{cases} \frac{dm}{dt} = \dot{m}_{in} - \dot{m}_{out}  \\ \dot{m}_{out}=\sqrt{m} \\ \dot{m}_{in}=10 \\ m(t=0)=0 \end{cases} \] Where \(m\) is the mass inside the tank, \( \dot{m}_{in}\) is the mass entering the tank and \( \dot{m}_{out}\) is the mass leaving the tank. Units: Kg for mass, minutes for time. Tip: \(\int_{0}^{y} \frac{1}{a - \sqrt{x}} \, dx = 2a \ln \left| \frac{a}{a - \sqrt{y}} \right| - 2\sqrt{y}\) Take a look at the following statements: 1. The time for the first tank to achieve 80% of it's steady-state mass would be roughly 27 minutes. 2. Assuming the second tank follow the same model from the first tank, but it's inlet is defined by the outlet of the first tank, after a very long time, the mass inside the tank would be roughly 10 Kg. 3. Assume that at a given time, the entire tank system behaves like the following flow network: The residual network related to the syste...